Help me understand Blue Laced Red Wyandotte color genetics!

Calleoop

Hatching
9 Years
Sep 22, 2010
3
1
7
Hi, I am trying to learn about the color genetics of Wyandottes, and especially the Blue Laced Reds. I have seen the color charts for Blues w/
black, blue & splashes, but am not understanding how this applies to the blue laced red color? How are they bred? I would love to hear
more information if anyone has a minute! Thank you!
 
The same BBS genetics that you've seen apply with BLRW, the red does not effect the outcomes of the crosses.

Blue X Blue = 50% Blue, 25% Black, 25% Splash
Blue X Splash = 50% Blue, 50% Splash
Blue X Black = 50% Blue, 50% Black
Splash X Black = 100% Blue
Black X Black = 100% Black
Splash X Splash = 100% Splash
 
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Thanks!

So if I was looking at a "Black" Blue Laced Red Wyandotte, what would I see? Would there still be blue lacing on the red with black
coloration where the blue/grey coloration on the lower parts is? Or is the blue lacing what would turn splash or black?

If I crossed a BLR, or BLR splash with a black wyandotte (not blue laced red), what qty of offspring would have the lacing?
 
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If the bird was black laced red there will be no blue at all. It would be a red bird with black lacing. That's exactly what it would look like.

The same applies to the other two color variations.
If it's a blue laced red than the feathers will be red with blue lacing. If it's a splash laced red the feathers will be red with white lacing.

Blue is a diluent of the color black. It basically "washes out" the black color, leaving the blue visible. Blue is essentially gray.

If you have 0 copies of the blue gene (say a Black Laced Red X Black Laced Red) the result will be black laced chicks.
If you have 1 copy of the blue gene (say a Blue Laced Red X Black Laced Red) the result will be blue and black laced chicks.
If you have 2 copies of the gene (say Blue Laced Red X Blue Laced Red) the result will be blue, black and splash laced chicks.
You must have 2 copies (2 birds that are visibly blue) to have splash colored chicks. Splash X Splash will always result in splash chicks, laced or otherwise.

Hope I helped!
 
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Ok, now we're getting somewhere!! I think I am understanding.

So if you took one of those laced birds and crossed them to a non-laced bird, would you get whatever color as mentioned, with half qty laced?
Thanks so much for the info; I hadn't seen this really discussed anywhere so far!
 
Hm, it depends on both of the birds genetic make up, you may or may not get birds with lacing. Also the same rule applies for the color blue when crossing to different breeds. Say you crossed a Blue Laced Red Wyandotte with a Black Ameraucana. I'm not sure if the resulting chicks would be laced but there would be a chance for blue and black chicks to hatch. Due to the Blue X Black breeding.

I know when you cross Wyandotte colors you get some pretty interesting results. Sometimes by crossing two different varieties you can get mixed looking birds OR birds that look like one parent or the other, but can still carry the recessive color genetics. It all depends on what you breed together.

What matings did you have in mind?
 
Single lacing is made by a combination of Pattern,Melanotic & Columbian genes, these with gold give gold/red laced as in Gold Laced Wyandotte; on silver you get Silver Laced; add blue & you get Blue Laced Red ,on silver Violet (Blue) Laced.
If you want to increase your birds you can use BLR or BLR Splash over Gold Laced hens.

Mating a laced bird to a self coloured bird will destroy the lacing for a few generations at least.
 
So you would breed a BLRW with what color Wyandotte in order to get the Violet Laced birds?
How many generations would this take?
 
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My f1 BLR Cochins are now 3 months old. As predicted, my GL roo x Splash hen has yielded me 100% Blues (solid with no GL lacing). I have held back the best pullets, and they will be bred back to the sire GL roo when of age. I plan to repeat this process for however many generations it takes to get the lacing visible and up to standard.

Here's my question: What if I take the same steps as above, only this time replace the Splash hen with a Self-Blue hen? I understand the Self-Blue gene should breed true, in that it is not incomplete dominant like the Andalusian Blue gene, but will it still dilute the black lacing to Blue? In a few generations, would I have the same phenotype bird using Self-Blue instead of Splash?
 
So you would breed a BLRW with what color Wyandotte in order to get the Violet Laced birds?
A Silver Laced cock over BLRW hens will give 25% each (large numbers) Silver Laced pullets;Violet Laced pullets; split silver gold & split blue silver/gold cockerels. Mate the Violet Laced pullets to a Silver Laced cock bird and you will get 50% Silver Laced & Violet Laced.

Here's my question: What if I take the same steps as above, only this time replace the Splash hen with a Self-Blue hen? I understand the Self-Blue gene should breed true, in that it is not incomplete dominant like the Andalusian Blue gene, but will it still dilute the black lacing to Blue? In a few generations, would I have the same phenotype bird using Self-Blue instead of Splash?
By Self-Blue I presume you mean Lavender. A Gold Laced cock over Lavender hens will give black chicks, these will carry one copy of Lavender,Pattern,Columbian & Melanotic. The cock bird will most likely be Brown & Gold based; the hen Extended Black & Silver. Mating these F1 birds together (& it will need a large hatch or a lot of luck) you will get mostly Black or Lavender birds, but also some Gold Laced,Silver Laced, Silver with Lavender Lacing, & Isabel ( the pale cream as in Porcelain Belgians) with Lavender Lacing.
As Lavender dilutes gold as well as black you will not be able to a dark red/gold bird with lavender lacing.
 

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