Wyandotte Genetics

It's hard to say what combinations you can expect without knowing for sure what the genetics of your birds are. Gold and silver laced are pretty straightforward, being long established varieties. The blue, splash and "buff" laced are a little tricker because it's more difficult to tell what color modifiers are in play. Your "buff" laced could just be a blr without the mahogany gene.

At any rate, a gold laced rooster over a silver laced hen will produce sex linked chicks (gold females and solver males with gold leakage). Either male over your splash laced hen will produce chicks with blue lacing. Silver is dominant to red, so your silver laced rooster over any of those hens will give you silver chicks (with gold leakage in the case of chicks from any of your gold/red based hens)
 
Thank you so much for the reply! You must be very knowledgeable! Are “Buff” wyandottes not an actual colour in wyandottes? And do splash laced have a blue gene? Thanks
 
Like from example if I crossed a gold laced with a splash laced it would make a gold laced blue? And with the sex-linked cross, would you be able to tell from hatch the boys from the girls? Like legbars and other breeds?
 
What if I keep a Buff Rooster or Splash Laced? Sorry for so many questions. I am just trying to find out future breeding.
 
I dabble in genetics, there are others here who are much more knowledgeable. Blue just happens to be one of the genes that interest me and I like blr wyandottes.

Yes, splash laced crossed with gold laced will result in blue laced (I'm much less sure of the inheritance of red vs gold though). This is because of how the gene for blue works. It is incomplete dominant. A single copy of the gene dilutes black to blue. Two copies dilutes it even more, to black.

So if you breed two black birds, you get 100% black chicks.
If you breed blue to black, 50% of the chicks will inherit a blue gene from the blue parent and will be blue. The other 50% will be black.
If you breed two blue birds, 50% will inherit only one blue gene from one of the parents and will be blue. 25% will not inherit a blue gene from either parent and will be black. And 25% will inherit a blue gene from each parent and will be splash.
So if a splash bird has two copies of the blue gene, they will pass a copy on to 109% of their chicks. This means if you breed splash to black, each chick will inherit the blue gene from the splash parent and a black gene from the black parent and 100% of the offspring will be blue.
If you breed blue to splash, 50% will inherit a blue gene from each parent and be splash. The other 50% will be blue.

Silver turns red/gold pigment white. Silver is dominant to gold. While silver is completely dominant, in real life it isn't quite cut and dry in real life. Males with only one silver gene will usually have some gold color leakage.

Silver is also sex linked. It is carried on the Z chromosome (birds are "swapped" compared to mammals-females are ZW and makes are ZZ). So a silver female will always have one gene for silver and one gene for not silver (gold). Silver males could have either one gene or two genes for silver, in the case of birds from a breeder or hatchery it can generally be assumed they have two copies. Since hens can only pass a Z chromosome to male offspring, any female offspring can only inherit a not silver gene from her with the W chromosome.
That's why a gold rooster (with zero copies of the silver gene) over a silver hen (with one copy of silver on the Z chromosome and one copy of not silver on the W chromosome) will create silver males (ZZ, with one gene for silver on the Z chromosome inherited from the hen and one gene for not silver on the Z chromosome inherited from the rooster) and gold females (one gene for not silver inherited from the hen on the W chromosome and one gene for not silver inherited on the Z chromosome from the rooster).
 
I think I will keep a Buff Laced rooster instead of the silver, so that there is more variety in the chicks.
 

New posts New threads Active threads

Back
Top Bottom